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To find the volume of the gas at 470. mmHg, we need to use the combined gas law equation:
(P1)(V1) = (P2)(V2)
Where:
P1 = initial pressure = 4.0 atm
V1 = initial volume = 4.5 L
P2 = final pressure = 470. mmHg = 0.618 atm (1 atm = 760 mmHg)
V2 = final volume (unknown)
Plugging in the values:
(4.0 atm)(4.5 L) = (0.618 atm)(V2)
18.0 atm*L = 0.618 atm * V2
V2 = 29.1 L
Therefore, the volume of the gas at 470. mmHg is 29.1 L.