Question

Scatter Plots & Data Analysis Unit Test

7 of 157 of 15 Items

Question
Use the image to answer the question.

An illustration of a scatterplot graph shows x-axis ranging from 0 to 15 in increments of 1 and y-axis ranging from 0 to 75 in increments of 5. Multiple points are plotted and a line points upward to the right with an arrowhead on the top.
The line passes approximately through left parenthesis 0 comma 25 right parenthesis, left parenthesis 1 comma 30 right parenthesis, left parenthesis 2 comma 35 right parenthesis, left parenthesis 7 comma 60 right parenthesis, and left parenthesis 10 comma 75 right parenthesis. 5 points are plotted to the line.

Write an equation in slope-intercept form of the trend line.

(1 point)

Answer 1

[AI-generated answer — Bot GPT 3.5]

To write the equation of the trend line in slope-intercept form, we need to find the slope and the y-intercept.

Using the points (0, 25) and (10, 75), we can calculate the slope:

slope = (75 - 25) / (10 - 0)
slope = 50 / 10
slope = 5

Next, we can use one of the points to find the y-intercept. Let's use (0, 25):

y = mx + b
25 = 5(0) + b
25 = b

Therefore, the equation of the trend line in slope-intercept form is:

y = 5x + 25