To calculate the mass of chloride ion used in the titration, we need to consider the stoichiometry of the reaction between silver nitrate (AgNO3) and sodium chloride (NaCl).
The balanced chemical equation for the reaction is:
AgNO3 + NaCl → AgCl + NaNO3
From the equation, we can see that 1 mole of silver nitrate reacts with 1 mole of sodium chloride to form 1 mole of silver chloride.
Given that the molarity of silver nitrate solution used is 0.1 mol/L and the volume used is 10 ml (0.01 L), we can calculate the number of moles of silver nitrate used:
0.1 mol/L x 0.01 L = 0.001 mol
Since the reaction stoichiometry is 1:1, the number of moles of silver chloride formed is also 0.001 mol.
The molar mass of silver chloride (AgCl) is approximately 143.32 g/mol. Therefore, the mass of chloride ion present in the solution used for titration can be calculated as follows:
0.001 mol x 143.32 g/mol = 0.14332 g
So, the mass of chloride ion used in the titration would be approximately 0.14332 grams.