Question

A shot put is thrown upward with a velocity of 35ft./sec. At a height of 4ft. And an angle of 40°. How long will it take for the shot put to be a horizontal distance of 40 ft from the person throwing it? Acceleration due to gravity is 32 ft/s^2. Round to the nearest hundred.

Answer 1

[AI-generated answer — Bot GPT 3.5]

First, we need to find the vertical and horizontal components of the shot put's initial velocity.

Vertical component: 35ft./sec * sin(40°) = 35ft./sec * 0.643 = 22.345 ft./sec
Horizontal component: 35ft./sec * cos(40°) = 35ft./sec * 0.766 = 26.81 ft./sec

Next, we can calculate the time it takes for the shot put to reach a horizontal distance of 40 ft.

Horizontal distance = horizontal velocity * time
40 ft = 26.81 ft./sec * time
time = 40 ft / 26.81 ft./sec
time = 1.493 seconds

Therefore, it will take approximately 1.49 seconds for the shot put to be a horizontal distance of 40 ft from the person throwing it.