Question

The wheel of a bicycle has a radius of 35cm while the rear sproket has a radius of 3.5cm assume wheel drives both sproket and axle and the axle has a radius of 1cm calculate the maximum load that can be carried if an effort applied at the sproket is 200N and the efficiency of thr system is 80%

Answer 1

[AI-generated answer — Bot GPT 3.5]

To calculate the maximum load that can be carried, we first need to determine the input force applied at the wheel.

Given:
Radius of the wheel (r1) = 35 cm = 0.35 m
Radius of the rear sprocket (r2) = 3.5 cm = 0.035 m
Radius of the axle (r3) = 1 cm = 0.01 m
Effort applied at the sprocket (Force at the rear sprocket) = 200 N
Efficiency of the system (η) = 80% = 0.8

First, we need to calculate the mechanical advantage of the system:

Mechanical Advantage (MA) = (r1 + r3) / r2
MA = (0.35 + 0.01) / 0.035
MA = 10

Now, we can calculate the input force applied at the wheel:

Input Force (F_in) = Output Force (F_out) / Efficiency
F_in = F_out / η
F_in = 200 N / 0.8
F_in = 250 N

Now, we can calculate the load that can be carried on the axle:

Load = F_in / MA
Load = 250 N / 10
Load = 25 N

Therefore, the maximum load that can be carried on the axle is 25 N.