Use Nets to Solve Triangular Problems Quick Check

1 of 51 of 5 Items
Question
Use the image to answer the question.

An illustration shows a triangular prism placed sideways with one of its rectangular faces as the base. Dimensions are labeled. The length and width of the rectangular base are 17 centimeters and 13 centimeters respectively. The face visible in front appears as a triangle. The base width of the triangle is 13 centimeters. The perpendicular leg of the triangle is 7.48 centimeters and the slanting leg (hypotenuse) is 15 centimeters. The edges that are not visible are represented by dashed lines.

Apply the technique of using nets to find the surface area of this triangular prism. Your answer should have two decimal places.

(1 point)
Responses

603.16 cm2
603.16 cm squared

97.24 cm2
97.24 cm squared

573.24 cm2
573.24 cm squared

700.40 cm2
700.40 cm squared

Bot GPT 3.5 Bot GPT 3.5 answered
1 month ago

603.16 cm2

♥Escapism♥ ♥Escapism♥ answered
1 month ago

Use the image to answer the question.



An illustration shows a 2 D net of a triangular prism with all of its sides open and visible. Dimensions are labeled. The parts that are not visible in 3 D view are marked with dashed lines. It appears as three vertical rectangles placed vertically. The length and width of the top rectangle are 6.5 feet and 5 feet respectively. The length and width of the middle rectangle are 5.5 feet and 5 feet respectively. The length of the bottom rectangle is 5 feet. Two identical triangles adjoin the middle rectangle on both sides with legs measuring 3.5 feet and 5.5 feet. The hypotenuse measures 6.5 feet.

Write an equation for the surface area of both triangular bases of the net.

(1 point)
Responses

SA=12(3.5)(5)
upper S upper A equals Start Fraction 1 over 2 End Fraction left parenthesis 3.5 right parenthesis left parenthesis 5 right parenthesis

SA=2(12)(3.5)(5.5)
upper S upper A equals 2 left parenthesis Start Fraction 1 over 2 End Fraction right parenthesis left parenthesis 3.5 right parenthesis left parenthesis 5.5 right parenthesis

SA=2(12)(6.1)(3.5)
upper S upper A equals 2 left parenthesis Start Fraction 1 over 2 End Fraction right parenthesis left parenthesis 6.1 right parenthesis left parenthesis 3.5 right parenthesis

SA=(12)(5)(6.5)

Bot GPT 3.5 Bot GPT 3.5 answered
1 month ago

upper S upper A equals 2 left parenthesis Start Fraction 1 over 2 End Fraction right parenthesis left parenthesis 3.5 right parenthesis left parenthesis 5.5 right parenthesis

♥Escapism♥ ♥Escapism♥ answered
1 month ago

Use Nets to Solve Triangular Problems Quick Check

3 of 53 of 5 Items

Question
The 2005 world record for the longest sandwich is 3.6 meters with a width of 3.6 meters and a thickness of 0.44 meters. If you cut the sandwich in half diagonally, it would create a triangular prism with a hypotenuse of 5.1 meters. Apply the technique of using nets to find the surface area.(1 point)
Responses

14.63 m2
14.63 m squared

12.98 m2
12.98 m squared

16.22 m2
16.22 m squared

18.37 m2
18.37 m squared

Bot GPT 3.5 Bot GPT 3.5 answered
1 month ago

12.98 m2

♥Escapism♥ ♥Escapism♥ answered
1 month ago

A triangular prism has a height of 1.5 inches and right triangular bases with a height of 1.5 inches, length of 5 inches, and a hypotenuse measuring 5.22 inches. What is the prism's surface area? (1 point)

Responses

30.33 in.2
30.33 in. squared

25.41 in.2
25.41 in. squared

25.08 in.2
25.08 in. squared

24.75 in.2

Bot GPT 3.5 Bot GPT 3.5 answered
1 month ago

30.33 in.2

♥Escapism♥ ♥Escapism♥ answered
1 month ago

Calculate the surface area of a triangular prism shaped tent if the height is 9 ft., the length is 24 ft., the width is 20 ft., and the hypotenuse of the cover is 13.45 ft.(1 point)

Responses

982.8 ft.2
982.8 ft. squared

1,462.80 ft.2
1,462.80 ft. squared

1,305.60 ft.2
1,305.60 ft. squared

1,215.60 ft.2
1,215.60 ft. squared

Bot GPT 3.5 Bot GPT 3.5 answered
1 month ago

To calculate the surface area of a triangular prism, we need to find the areas of the two triangular bases and the three rectangular faces.

Given:
- Height (h) = 9 ft.
- Length (l) = 24 ft.
- Width (w) = 20 ft.
- Hypotenuse of the cover = 13.45 ft.

The triangular base is a right triangle with l = 24 ft., w = 20 ft., and hypotenuse h = 13.45 ft.
Using the Pythagorean theorem, we can find the height of the triangle base:
h^2 = l^2 + w^2
h^2 = 24^2 + 20^2
h^2 = 576 + 400
h^2 = 976
h ≈ √976
h ≈ 31.24 ft.

Now we can calculate the surface area:
1. Calculate the area of the two triangular bases:
Base Area = (1/2) * base * height
Base Area = (1/2) * 24 * 20 = 240 ft²

2. Calculate the area of the three rectangular faces:
Rectangular Face 1:
Area = length * height = 24 * 9 = 216 ft²
Rectangular Face 2:
Area = width * height = 20 * 9 = 180 ft²
Rectangular Face 3:
Area = hypotenuse * height = 13.45 * 9 = 121.05 ft²

Total Surface Area = 2(Base Area) + 3(Sum of Rectangular Faces)
Total Surface Area = 2(240) + 3(216 + 180 + 121.05)
Total Surface Area = 480 + 1535.05
Total Surface Area ≈ 2015.05 ft²

Therefore, the surface area of the triangular prism-shaped tent is approximately 2015.05 ft².

🤔 🤔 Ask a New Question 🤔 🤔