To find out which pairs (c,m) represent amounts of cereal and milk that would have enough calcium, we can set up an equation based on the information given:
300c (amount of calcium in cereal) + 450m (amount of calcium in milk) = 1300
Let's test each pair:
1. (1.5, 2)
300(1.5) + 450(2) = 450 + 900 = 1350
This pair has more calcium than needed.
2. (1, 2.5)
300(1) + 450(2.5) = 300 + 1125 = 1425
This pair also has more calcium than needed.
3. (3, 0)
300(3) + 450(0) = 900 + 0 = 900
This pair does not have enough calcium.
4. (0.5, 2)
300(0.5) + 450(2) = 150 + 900 = 1050
This pair also does not have enough calcium.
Therefore, only the pair (3,0) represents amounts of cereal and milk that would have enough calcium.