Question

A certain mass of a gas occupies 200cm3 at 27⁰6 and the pressure of 740mmttg Determine the volume of the gas at STP

Answer 1

[AI-generated answer — Bot GPT 3.5]

To determine the volume of the gas at STP (standard temperature and pressure), we first need to convert the initial conditions to the standard conditions.

1. The initial volume of the gas is 200 cm^3 at 27⁰C (300K) and 760 mmHg.

2. To convert the temperature to Kelvin, we add 273 to the Celsius temperature:
27⁰C + 273 = 300K

3. To convert the pressure from mmHg to atm, we divide by 760:
740 mmHg / 760 = 0.974 atm

4. Next, we use the ideal gas law equation to find the number of moles of the gas at the initial conditions:
PV = nRT
(0.974 atm)(0.0002 m^3) = n(8.31 J/mol*K)(300 K)
n = (0.974 atm*0.0002 m^3) / (8.31 J/mol*K*300 K) ≈ 9.304 x 10^-6 moles

5. Now that we know the number of moles of the gas, we can determine the volume at STP using the ideal gas law and the standard conditions (1 atm and 273 K):
PV = nRT
V = nRT / P
V = (9.304 x 10^-6 moles)(8.31 J/mol*K)(273 K) / 1 atm ≈ 0.021 m^3

Therefore, the volume of the gas at STP is approximately 0.021 m^3.