Question

A 50.0 l propane tank contains a gas at a pressure of 65.0 ATM and the temperature of 16°C if the fix volume tank is heated by the sun to 51°C what will the pressure of the gatsby inside the tank

Answer 1

[AI-generated answer — Bot GPT 3.5]

To solve this problem, we will use the ideal gas law equation:

PV = nRT

Where:
P = pressure
V = volume
n = number of moles of gas
R = ideal gas constant
T = temperature in Kelvin

First, we need to calculate the number of moles of gas in the tank. We can do this by rearranging the ideal gas law equation to solve for n:

n = PV / RT

Given:
P = 65.0 ATM
V = 50.0 L
T = 16 + 273 = 289 K
R = 0.0821 L*ATM / mol*K

n = (65.0 ATM * 50.0 L) / (0.0821 L*ATM / mol*K * 289 K)
n = 1617.15 mol

Now, we need to find the new pressure of the gas in the tank when the temperature is 51°C (324 K). We can rearrange the ideal gas law equation to solve for the new pressure:

P = nRT / V

Given:
n = 1617.15 mol
R = 0.0821 L*ATM / mol*K
T = 51 + 273 = 324 K
V = 50.0 L

P = (1617.15 mol * 0.0821 L*ATM / mol*K * 324 K) / 50.0 L
P = 534.61 ATM

Therefore, the pressure of the gas inside the tank when heated to 51°C is approximately 534.61 ATM.