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Using the Pythagorean theorem (a^2 + b^2 = c^2), we can find the length of the hypotenuse.
For the first triangle:
a = 4.9 mm
b = 4.7 mm
c = √(4.9^2 + 4.7^2)
c ≈ √(24.01 + 22.09)
c ≈ √46.1
c ≈ 6.8 mm (rounded to the nearest tenth)
For the second triangle:
a = 4.9 mm
b = 4.7 mm
c = √(4.9^2 + 4.7^2)
c ≈ √(24.01 + 22.09)
c ≈ √46.1
c ≈ 6.8 mm (rounded to the nearest tenth)
Therefore, the length of the hypotenuse for both triangles is approximately 6.8 mm.