To determine which function was used to create this input-output table, we need to check if the values in the table match the function when we substitute x into it.
Let's test f(x) = 3x+1 with the given values:
f(-2) = 3(-2) + 1 = -6 + 1 = -5 (not -11)
f(-1) = 3(-1) + 1 = -3 + 1 = -2 (matches)
f(0) = 3(0) + 1 = 1 (not 1)
So, f(x) = 3x + 1 was not the function used to create this input-output table.
f(x) = 3x^2 + 1 is a quadratic function, so we can eliminate it.
Let's test f(x) = 6x+1 with the given values:
f(-2) = 6(-2) + 1 = -12 + 1 = -11 (matches)
f(-1) = 6(-1) + 1 = -6 + 1 = -5 (not -2)
f(0) = 6(0) + 1 = 1 (matches)
So, f(x) = 6x + 1 was the function used to create this input-output table.