Question

The ages of randomly selected employees that two companies are recorded. Their ages are as follows: company A: 34, 28, 36, 27, 45, 44, 30, 42, 41, 40, 50, 48, 52, 45, 39, and 38. Company B: 29, 32, 48, 51, 49, 37, 33, 35, 36, 40, 45, 48, 43, 43, 44, and 48.

Answer 1

[AI-generated answer — Bot GPT 3.5]

To compare the ages of the employees at the two companies, we can calculate the mean, median, and mode for each company.

For company A:
Mean: (34 + 28 + 36 + 27 + 45 + 44 + 30 + 42 + 41 + 40 + 50 + 48 + 52 + 45 + 39 + 38) / 16 = 39.375
Median: since there are 16 ages, the median will be the average of the 8th and 9th values when arranged in ascending order. So the median is (40 + 41) / 2 = 40.5
Mode: The mode is the age that appears most frequently. In this case, 45 appears twice which is the highest frequency, so the mode is 45.

For company B:
Mean: (29 + 32 + 48 + 51 + 49 + 37 + 33 + 35 + 36 + 40 + 45 + 48 + 43 + 43 + 44 + 48) / 16 = 40.125
Median: since there are 16 ages, the median will be the average of the 8th and 9th values when arranged in ascending order. So the median is (40 + 43) / 2 = 41.5
Mode: The mode is the age that appears most frequently. In this case, 48 appears three times which is the highest frequency, so the mode is 48.

In conclusion, the mean age for employees at company A is 39.375 and at company B is 40.125. The median age at company A is 40.5 and at company B is 41.5. The mode age for both companies is different, with the mode being 45 for company A and 48 for company B.