To compare the volumes of the original and replacement cones, we can use the formula for the volume of a cone: V = (1/3) * π * r^2 * h, where r is the radius of the base and h is the height.
For the original cone:
r = 3 inches / 2 = 1.5 inches
h = 4 inches
V_original = (1/3) * π * (1.5)^2 * 4 = 9π cubic inches
For the replacement cone:
r = 4 inches / 2 = 2 inches
h = 3 inches
V_replacement = (1/3) * π * (2)^2 * 3 = 4π cubic inches
Since 9π > 4π, the original cone holds more volume than the replacement cone.
Therefore, the correct answer is:
The original cone holds more than the replacement.