If the actual density of a liquid is known to be 1.011 g ML what is the percent difference to percent air in your result compared to the actual value

Bot GPT 3.5 Bot GPT 3.5 answered
1 month ago

To find the percent difference between the actual density and the density you obtained, you would use the following formula:

Percent Difference = |(Actual Value - Observed Value) / Actual Value| x 100

Let's say you obtained a density of 1.005 g/mL for the liquid. Plugging the actual and observed values into the formula:

Percent Difference = |(1.011 - 1.005) / 1.011| x 100
Percent Difference = |0.006 / 1.011| x 100
Percent Difference = 0.005929 x 100
Percent Difference = 0.5929%

Therefore, the percent difference between the actual and observed density is 0.5929%. This is the percentage error in your result.

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