The probability of both events A and B happening at the same time is:
P(A and B) = P(A) * P(B) = 0.3 * 0.25 = 0.075
So, the probability of events A and B happening at the same time is 0.075 in decimal form.
If two events are independent, the probability of both events occurring is the product of their individual probability. Events A and B are independent with P(A)=0.3 and P(B)=0.25 . What is the probability of events A and B happening at the same time? Write your answer in decimal form.
P(A and B) = P(A) * P(B) = 0.3 * 0.25 = 0.075
So, the probability of events A and B happening at the same time is 0.075 in decimal form.
Studying Online
Girls Boys Row total
Want the option to keep studying online 10 3 13
Donβt want the option to keep studying online 5 7 12
Column total 15 10 25What is the probability of selecting a student who wants the option to keep studying online? Write your answer in percent form.
The total number of students in the sample is 25.
So, the probability of selecting a student who wants the option to keep studying online is:
P(student wants to keep studying online) = Number of students who want to keep studying online / Total number of students
P(student wants to keep studying online) = 13 / 25 = 0.52
Converting this to percentage form: 0.52 * 100% = 52%
Therefore, the probability of selecting a student who wants the option to keep studying online is 52% in percent form.
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Question
A money envelope contains five $10 bills, ten $20 bills, and fifteen $50 bills. Sandra randomly selects two bills without returning the first bill. What is the probability of getting a $10 bill then a $50 bill? Write your answer in the simplest form of fraction.
Total number of bills = 5 (from $10 bills) + 10 (from $20 bills) + 15 (from $50 bills) = 30 bills
Total number of outcomes when selecting two bills = 30 * 29 (she doesn't return the first bill) = 870 outcomes
The number of ways to get a $10 bill and then a $50 bill can be calculated as:
Number of ways to get a $10 bill = 5 (from $10 bills)
Number of ways to get a $50 bill = 15 (from $50 bills)
Therefore, the total number of ways to get a $10 bill followed by a $50 bill = 5 * 15 = 75 ways
The probability of this happening is the number of favorable outcomes (getting a $10 bill followed by a $50 bill) divided by the total number of outcomes:
Probability = Number of favorable outcomes / Total number of outcomes
Probability = 75 / 870
Probability = 15 / 174
Therefore, the probability of getting a $10 bill followed by a $50 bill is 15/174 in the simplest form of a fraction.
The total number of bills = 5 (from $10 bills) + 10 (from $20 bills) + 15 (from $50 bills) = 30 bills
When Sandra selects the first bill, the total number of bills decreases by 1, so the total number of outcomes for her second selection would be 30 - 1 = 29.
The number of ways to get a $10 bill on the first draw is 5.
The number of ways to get a $50 bill on the second draw, given that the $10 bill was selected first, is 15.
Therefore, the total number of ways to get a $10 bill followed by a $50 bill is 5 * 15 = 75 ways.
So the probability of selecting a $10 bill then a $50 bill is:
Probability = Number of favorable outcomes / Total number of outcomes
Probability = 75 / (30 * 29)
Probability = 75 / 870
Probability = 5 / 58
Therefore, the probability of getting a $10 bill then a $50 bill is 5/58.