To find the slant height x of the pyramid, we can use the Pythagorean theorem.
Consider the right triangle formed by the slant height x, half the side of the square base (3.5 mm), and the height of the pyramid (6 mm).
Using the Pythagorean theorem:
x^2 = (3.5)^2 + 6^2
x^2 = 12.25 + 36
x^2 = 48.25
x = sqrt(48.25)
x ≈ 6.9 mm
Therefore, the slant height x of the pyramid is approximately 6.9 mm.
The closest option is:
6.9 mm