Question

Use the image to answer the question.

An illustration shows a two-dimensional net of a triangular prism with all of its sides open and visible. The net appears as three vertical rectangles joined one on top of the other. All 4 sides of the middle rectangle are drawn with dashed lines. The width of the rectangles is 7 millimeters. The length of the middle rectangle is 8 millimeters. Two right triangles adjoin the middle rectangle on the left and the right, with the perpendicular sides measuring 6 millimeters and the hypotenuse measuring 10 millimeters.

Using the net of the prism shown, what is its surface area?

(1 point)
mm2

Answer 1

[AI-generated answer — Bot GPT 3.5]

To find the surface area of the triangular prism, we need to calculate the area of each of the three rectangles and the two triangles.

The area of each rectangle is length x width. So, the area of the top and bottom rectangles is 8 mm x 7 mm = 56 mm^2 each. The area of the middle rectangle is 6 mm x 7 mm = 42 mm^2.

The area of each triangle is 1/2 x base x height. In this case, the base of each triangle is 6 mm and the height is 8 mm. So, the area of each triangle is 1/2 x 6 mm x 8 mm = 24 mm^2 for both triangles.

Adding all these areas together, we get:
56 mm^2 (top) + 56 mm^2 (bottom) + 42 mm^2 (middle) + 24 mm^2 (left triangle) + 24 mm^2 (right triangle) = 202 mm^2

Therefore, the surface area of the triangular prism is 202 mm^2.

Answer 2

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