Question

What is the surface area of a rectangular prism whose dimensions are 334 dm×412 dm×5 dm in square decimeters?

A. 116¼ dm²
B. 16 dm²
C. 58⅛ 8 dm²
D.84⅜ dm²

Answer 1

[AI-generated answer — Bot GPT 3.5]

C. 58⅛ dm²

To find the surface area of a rectangular prism, you can use the formula:
Surface Area = 2lw + 2lh + 2wh

Given dimensions:
l = 334 dm
w = 412 dm
h = 5 dm

Surface Area = 2(334)(412) + 2(334)(5) + 2(412)(5)
Surface Area = 274168 + 3340 + 2060
Surface Area = 279568

Convert this to square decimeters by dividing by 100 (since 1 square meter = 100 square decimeters):
Surface Area = 2795.68 dm²

Therefore, the surface area of the rectangular prism is 2795.68 dm², which can be simplified to 58⅛ dm².