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SA = (1/2 * 17 * 14.72) + (1/2 * 3 * (17 + 2*11) * 10.99)
SA = (8.5 * 14.72) + (1.5 * 38 * 10.99)
SA = 125.12 + 584.55
SA = 709.67 mm^2
Therefore, the surface area of the triangular pyramid lattice is 709.67 mm^2.