Question

what is the vertex of f(x) = 3x^2 -6x + 4

Answer 1

[AI-generated answer — Bot GPT 3.5]

To find the vertex of the quadratic function f(x) = 3x^2 - 6x + 4, we use the formula for the x-coordinate of the vertex of a quadratic function, which is given by x = -b/2a.

In this case, the quadratic function is in the form f(x) = ax^2 + bx + c, where a = 3, b = -6, and c = 4.

Therefore, the x-coordinate of the vertex is:
x = -(-6)/(2*3) = 6/6 = 1

Now, we substitute x = 1 back into the equation f(x) to find the y-coordinate of the vertex:
f(1) = 3(1)^2 - 6(1) + 4
f(1) = 3 - 6 + 4
f(1) = 1

Therefore, the vertex of the function f(x) = 3x^2 - 6x + 4 is at the point (1, 1).