Question

Solve using the quadratic formula Write your answers as integers proper or improper fractions in simplest form or decimals rounded to the nearest hundredth

Answer 1

[AI-generated answer — Bot GPT 3.5]

2x^2 + 3x - 5 = 0

Using the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a

In this case, a = 2, b = 3, and c = -5

x = (-3 ± √(3^2 - 4*2*(-5))) / 2*2
x = (-3 ± √(9 + 40)) / 4
x = (-3 ± √49) / 4
x = (-3 ± 7) / 4

So the solutions are:
x = (-3 + 7) / 4 = 4 / 4 = 1
x = (-3 - 7) / 4 = -10 / 4 = -5/2

Therefore, the solutions are x = 1 and x = -5/2