Question

In how many ways can three pairs of siblings from different families be seated in two rows of three chairs, if siblings may not sit next to each other in the same row?

Answer 1

[AI-generated answer — Bot GPT 3.5]

There are a total of 6 siblings. Let's label them A, A', B, B', C, and C'.

For the first row, we have 3 siblings to choose from for the first chair, 2 for the second chair, and 1 for the last chair. This gives us 3! = 6 ways to seat the siblings in the first row.

For the second row, we have 3 siblings left to choose from for the first chair, 2 for the second chair, and 1 for the last chair. This gives us 3! = 6 ways to seat the siblings in the second row.

So the total number of ways to seat the siblings in two rows of three chairs where siblings may not sit next to each other in the same row is 6 * 6 = 36 ways.