Question

Probability of Chance Events Quick Check

2 of 52 of 5 Items

Question
The letter tiles C, A, R, E , and S are placed in a box. Without looking, Jorelle picks a letter tile from the box and records the result before placing it back. He repeats the procedure 100 times and observes the following results:

Outcomes C A R E S
Frequency 20 25 30 10 15
Based on the observed frequency, develop a probability model for this experiment. Express the probability in decimal form, rounded to the nearest hundredth.

(1 point)
Responses

X C A R E S
P(X) 0.20 0.30 0.25 0.10 0.15X C A R E S P(X) 0.20 0.30 0.25 0.10 0.15

X C A R E S
P(X) 0.25 0.25 0.35 0.15 0.15X C A R E S P(X) 0.25 0.25 0.35 0.15 0.15

X C A R E S
P(X) 0.20 0.25 0.30 0.10 0.15X C A R E S P(X) 0.20 0.25 0.30 0.10 0.15

X C A R E S
P(X) 0.02 0.03 0.03 0.01 0.015

Answer 1

[AI-generated answer — Bot GPT 3.5]

Correct response: X C A R E S P(X) 0.20 0.30 0.25 0.10 0.15

Answer 2

Probability of Chance Events Quick Check

4 of 54 of 5 Items

Question
Use the tables to answer the question.

Simon’s Results

Number of White Balls Selected Number of Red Balls Selected
Bowl A 5 15
Bowl B 16 4
Clark’s Results

Number of White Balls Selected Number of Red Balls Selected
Bowl A 45 55
Bowl B 60 40
Bowls A and B contain a number of white and red balls. Simon and Clark repeatedly selected a ball from both bowls and recorded the results in a table. Whose results will give you a better indication about the proportion of white and red balls in each bowl? Explain your answer.

(1 point)
Responses

Both results can be used, as they performed the experiment at random.
Both results can be used, as they performed the experiment at random.

Simon’s experiment. He conducted a greater number of trials than Clark.
Simon’s experiment. He conducted a greater number of trials than Clark.

Neither; they conducted the same number of trials.
Neither; they conducted the same number of trials.

Clark’s experiment. He conducted a greater number of trials than Simon.

Answer 3

[AI-generated answer — Bot GPT 3.5]

Simon’s experiment. He conducted a greater number of trials than Clark.

Explanation: Simon's results will give a better indication because he conducted more trials which allows for a more accurate representation of the proportions of white and red balls in each bowl.

Answer 4

Probability of Chance Events Quick Check

5 of 55 of 5 Items

Question
Use the table to answer the question.

Number of White Balls Selected Number of Red Balls Selected
Bowl A 5 15
Bowl B 16 4
Bowls A and B contain a number of white and red balls. Simon repeatedly selected a ball from both bowls and recorded the results in a table. Using Simon’s results, what is the experimental probability of picking a red ball from Bowl A? The answer needs to be in percent form.

(1 point)
Responses

25%
25%

37.5%
37.5%

75%
75%

78.95%
78.95%

Answer 5

[AI-generated answer — Bot GPT 3.5]

To find the experimental probability of picking a red ball from Bowl A, we look at the data provided for picking red balls from Bowl A and Bowl B.

For Bowl A: Number of Red Balls Selected = 15
Total number of selections from Bowl A = 5 (white) + 15 (red) = 20

Experimental probability of picking a red ball from Bowl A = 15 / 20 = 0.75

Convert the decimal to percent: 0.75 * 100 = 75%

So, the correct answer is: 75%

Answer 6

1) .72

2) xcares: .20, .25, .30, .10, .15
3) the graph where all bars are at .2
4) Clarks experiment, he conducted more trials.
5)75%