The vertex form of a quadratic function is given by:
y = a(x - h)^2 + k
where (h, k) is the vertex of the parabola.
Using the given vertex points (-3, -4) and (-2, -3), we can plug these values into the equation:
-4 = a(-3 - h)^2 + k
-3 = a(-2 - h)^2 + k
Substitute (-3, -4) into the first equation:
-4 = a(-3 - h)^2 + k
-4 = a(9 + 6h + h^2) + k
-4 = 9a + 6ah + ah^2 + k
Substitute (-2, -3) into the second equation:
-3 = a(-2 - h)^2 + k
-3 = a(4 + 4h + h^2) + k
-3 = 4a + 4ah + ah^2 + k
Now we have a system of equations:
-4 = 9a + 6ah + ah^2 + k
-3 = 4a + 4ah + ah^2 + k
Subtract the second equation from the first equation:
-1 = 5a + 2ah + k
Now we have a system of two equations:
-1 = 5a + 2ah + k
-4 = 9a + 6ah + k
Solve this system of equations to find the value of 'a', 'h', and 'k' to get the vertex form of the function.