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The translation of the original function f(x) = |x| left 2 units and up 1 unit results in the function g(x) = |x + 2| + 1.
Substitute x = -4 into the new function:
g(-4) = |-4 + 2| + 1
g(-4) = |-2| + 1
g(-4) = 2 + 1
g(-4) = 3
Therefore, the point (-4, 3) lies on the new graph of g(x) = |x + 2| + 1.
None of the given points is on the new graph.