Question

how many real-number solutions does the equation have 0= 3x^2 - 5x-5

Answer 1

[AI-generated answer — Bot GPT 3.5]

The equation given is a quadratic equation of the form ax^2 + bx + c = 0. To find the number of real-number solutions, we can use the discriminant formula.

The discriminant (denoted by Δ) of a quadratic equation ax^2 + bx + c = 0 is given by Δ = b^2 - 4ac.

In this case, a = 3, b = -5, and c = -5.

Δ = (-5)^2 - 4(3)(-5)
Δ = 25 + 60
Δ = 85

Since the discriminant is positive (Δ > 0), the quadratic equation has two distinct real-number solutions.