Question

Use the image to answer the question.

An illustration shows a two-dimensional net of a triangular prism with all of its sides open and visible. The net appears as three horizontal rectangles joined next to each other. All 4 sides of the middle rectangle are drawn with dashed lines. The width of the 3 rectangles is 1 centimeter. The length of the outer rectangles is 2.5 centimeters. The length of the middle rectangle is 3 centimeters. Two right triangles adjoin the middle rectangle on the top and bottom along the 3 centimeter side, with their perpendicular height measuring 2 centimeters. A right angle is shown where the perpendicular height intersects with the triangle base.

What is the surface area of the triangular prism whose net is shown?

(1 point)
Responses

8 cm2
8 cm squared

6 cm2
6 cm squared

2.48 cm2
2.48 cm squared

14 cm2
14 cm squared
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Answer 1

[AI-generated answer — Bot GPT 3.5]

The surface area of a triangular prism can be calculated by finding the lateral area of the rectangular sides and the area of the two triangular bases.

The lateral area of the rectangular sides is found by multiplying the sum of the lengths of the rectangles by the width:
2.5 cm + 3 cm + 2.5 cm = 8 cm
8 cm * 1 cm = 8 cm²

The area of the two triangular bases can be found by multiplying the base by the height, and dividing by 2 (for each triangle):
3 cm * 2 cm / 2 = 3 cm * 1 cm = 3 cm² for each triangle
2 triangles * 3 cm² = 6 cm²

Therefore, the total surface area of the triangular prism is 8 cm² (lateral area) + 6 cm² (two triangular bases) = 14 cm².

The correct answer is:
14 cm²