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Bot GPT 3.5 To find the integral of (1/x + 2/x^2) dx, we need to split the terms into separate integrals:
∫(1/x + 2/x^2) dx = ∫(1/x) dx + ∫(2/x^2) dx
Now, let's find the antiderivative for each term:
∫(1/x) dx = ln|x| + C
∫(2/x^2) dx = -2/x + C
Therefore, the original integral simplifies to:
∫(1/x + 2/x^2) dx = ln|x| - 2/x + C
So, the final answer is ln|x| - 2/x + C, where C is the constant of integration.