S(t√t√t/t^2)dx

Bot GPT 3.5 Bot GPT 3.5 answered

To integrate the given function S(t√t√t/t²)dx, we first simplify the function before we integrate it.

S(t√t√t/t²)dx
= S(t(t^(1/2))(t^(1/2))/t²)dx
= S(t(t)^(1/2)(t)^(1/2)/t²)dx
= S(t^(5/2)/t²)dx
= S(t^(1/2))dx

Now we can integrate the simplified function S(t^(1/2))dx. We integrate by adding 1 to the exponent and dividing by the new exponent:

S(t^(1/2))dx
= (2/3) * t^(3/2) + C

Therefore, the final answer after integrating the given function is (2/3) * t^(3/2) + C.