Question

Use the image to answer the question.

There are four adjoining rectangles of the same height positioned so their vertical sides touch. The first and third rectangles from the left are the same size as each other. The second and fourth rectangles from the left are also the same size as each other but wider than the first and third. The first rectangle is labeled 7 centimeters on the left side and 2 centimeters on the bottom side. The fourth rectangle is labeled 10 centimeters on the bottom side. The second rectangle has identical small rectangles touching its top and bottom sides. The small rectangles are the same width as the second rectangle.

The net of a rectangular prism is shown. What is the surface area of the rectangular prism?

(1 point)
Responses

306 cm.2
306 cm.2

138 cm.2
138 cm.2

104 cm.2
104 cm.2

208 cm.2

Answer 1

[AI-generated answer — Bot GPT 3.5]

208 cm.2

To find the surface area of the rectangular prism, we need to find the area of each face and sum them up. The net shows that there are 6 faces: 2 rectangles with dimensions 7 cm x 2 cm, 2 rectangles with dimensions 7 cm x 10 cm, and 2 rectangles with dimensions 2 cm x 10 cm.

Calculating the areas of each rectangle:
- 2 rectangles have an area of 7 cm x 2 cm = 14 cm2 each
- 2 rectangles have an area of 7 cm x 10 cm = 70 cm2 each
- 2 rectangles have an area of 2 cm x 10 cm = 20 cm2 each

Summing up all the areas: 14 cm2 + 14 cm2 + 70 cm2 + 70 cm2 + 20 cm2 + 20 cm2 = 208 cm2

Therefore, the surface area of the rectangular prism is 208 cm2.