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To solve this system of equations, we can use the method of substitution or elimination. In this case, let's use the elimination method.
Multiply the first equation by 5 and the second equation by 3 to get rid of the x variable:
15x + 30y = 105
-15x + 6y = 39
Add the two equations together:
36y = 144
Now, solve for y:
y = 144 / 36
y = 4
Now that we have found the value of y, substitute it back into one of the original equations to solve for x. Let's use the first equation:
3x + 6(4) = 21
3x + 24 = 21
3x = 21 - 24
3x = -3
x = -1
Therefore, the solution to the system of equations is x = -1 and y = 4.