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First, we can substitute the second equation into the first equation to eliminate x:
2(5y - 1) + 6y = -18
10y - 2 + 6y = -18
16y - 2 = -18
16y = -16
y = -1
Now that we have the value of y, we can substitute it back into the second equation to solve for x:
x = 5(-1) - 1
x = -5 - 1
x = -6
Therefore, the solution to the system of equations is (-6, -1), which corresponds to option B. (-6, -1).