The original and replacement cones have the same volume.
Volume of a cone = (1/3) * π * r^2 * h
For the original cone:
r = 1.5 inches, h = 4 inches
Volume = (1/3) * π * (1.5)^2 * 4 = 9π cubic inches
For the replacement cone:
r = 2 inches, h = 3 inches
Volume = (1/3) * π * (2)^2 * 3 = 8π cubic inches
Since 9Ï€ = 9 * 3.14 and 8Ï€ = 8 * 3.14, the volumes of the original and replacement cones are equal.