Question

How many real number solutions are there to the equation 0 = –3x² + x – 4?%0D%0A(1 point)

Answer 1

[AI-generated answer — Bot GPT 3.5]

To find the number of real number solutions to the equation 0 = -3x² + x - 4, we can use the discriminant of the quadratic equation.

The discriminant is given by Δ = b² - 4ac, where a = -3, b = 1, and c = -4 in the equation ax² + bx + c = 0.

Substitute the values of a, b, and c into the discriminant formula:

Δ = (1)² - 4(-3)(-4)
Δ = 1 - 12
Δ = -11

Since the discriminant (Δ) is negative (-11), there are no real number solutions to the equation 0 = -3x² + x - 4.