To solve this system of equations, we can use the method of elimination. Adding the two equations together will allow us to eliminate the variable y:
(6x - 5y) + (3x + 5y) = 27 + 36
9x = 63
x = 7
Now that we have found the value of x, we can substitute it back into either of the original equations to solve for y. Let's substitute x = 7 into the first equation:
6(7) - 5y = 27
42 - 5y = 27
-5y = -15
y = 3
Therefore, the solution to the system of equations is x = 7 and y = 3.