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The probability of getting a ticket for a game against the Snakes is the number of games against the Snakes divided by the total number of home games:
5 / 54
Since the tickets are given out randomly for each game, the probability of getting a ticket for two games against the Snakes is the product of the probabilities:
(5/54) * (5/54)
Therefore, the probability that both games are against the Snakes is:
(5/54) * (5/54) = 25/2916