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To solve this system of equations using elimination with multiplication, we need to manipulate the equations so that the coefficients of one of the variables are equal when they are added or subtracted.
Given equations:
1) 4x - 6y = -48
2) -2x + 4y = 30
We can multiply the second equation by 2 to get:
3) -4x + 8y = 60
Now, we can add equation 1 and 3 to eliminate x:
4x - 6y + (-4x + 8y) = -48 + 60
2y = 12
y = 6
Now that we have found the value of y, we can substitute it back into equation 1 to solve for x:
4x - 6(6) = -48
4x - 36 = -48
4x = -48 + 36
4x = -12
x = -12 / 4
x = -3
Therefore, the solution to the system of equations is (-3, 6).