Question

Graph a line wiege slope of -3/4 that contains the point (2,3)

Answer 1

[AI-generated answer — Bot GPT 3.5]

To graph a line with a slope of -3/4 that contains the point (2,3), we can use the point-slope form of a linear equation:

y - y1 = m(x - x1)

where:
m = slope = -3/4
(x1, y1) = (2,3)

Plugging in the values, we get:

y - 3 = (-3/4)(x - 2)

Simplify to:

y - 3 = (-3/4)x + (3/2)

Add 3 to both sides:

y = (-3/4)x + (3/2) + 3
y = (-3/4)x + 3/2 + 6/2
y = (-3/4)x + 9/2

Now we have the equation of the line:

y = (-3/4)x + 9/2

Now, plot the point (2,3) and use the slope to find another point on the line. The slope -3/4 means that for every 4 units you move to the right, you would move 3 units down. From the point (2,3), we can move 4 units to the right and 3 units down to get another point on the line:

(2+4, 3-3) = (6,0)

Now, plot these two points (2,3) and (6,0) on a graph and draw a straight line passing through them. This line represents the graph of the equation y = (-3/4)x + 9/2 with a slope of -3/4 and containing the point (2,3).