By setting up the equation 256 = (8)^x, we can solve for x:
Taking the log base 8 of both sides, we get:
log8(256) = x
Now, we know that 8^2 = 64 and 8^3 = 512. Since 256 is between 64 and 512, x must be between 2 and 3.
Taking the log base 8 of 256, we get:
log8(256) = 2.5
Therefore, it will take 2.5 rounds to go from 256 individuals trying out to the 8 individuals who will be on the Sunnyville High School Varsity Cheer Squad. Since we can't have half a round, we would need at least 3 rounds to complete the process.