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Given p( z > a) =0,7422 Find a
A)-0,53
B)0,58
C)0,72
D)0,68
E)-0,65
Given that P(z > a) = 0.7422, we need to find the value of a.
Using the standard normal distribution table, we can find the z-score corresponding to this probability of 0.7422.
Looking up the value in the z-table, we find that a z-score of approximately 0.63 corresponds to a probability of 0.7422.
Therefore, the answer is closest to option D) 0.68.