Question

Use the image to answer the question.

An illustration shows a triangular pyramid made with rows of chocolate covered candiesUse the image to answer the question.

An illustration shows a triangular pyramid made with rows of chocolate covered candies. The base measures 16 inches, the side of the triangular face measures 16 inches, and the vertical height is 13.86 inches.

Compute the surface area of the chocolate tower.

(1 point)
Responses

1,884.96 in.2
1,884.96 in. squared

443.52 in.2
443.52 in. squared

554.4 in.2
554.4 in. squared

460.64 in.2. The base measures 16 inches, the side of the triangular face measures 16 inches, and the vertical height is 13.86 inches.

Compute the surface area of the chocolate tower.

(1 point)
Responses

1,884.96 in.2
1,884.96 in. squared

443.52 in.2
443.52 in. squared

554.4 in.2
554.4 in. squared

460.64 in.2

Answer 1

[AI-generated answer — Bot GPT 3.5]

To compute the surface area of the triangular pyramid, we need to calculate the area of the triangular faces and the area of the base.

Area of each triangular face = (1/2) * base * height
= (1/2) * 16 * 13.86
= 111.36 in^2

Total area of all triangular faces = 3 * 111.36 = 334.08 in^2

Area of the base = 16^2 = 256 in^2

Surface area = Total area of all triangular faces + Area of the base
= 334.08 + 256
= 590.08 in^2

Therefore, the surface area of the chocolate tower is approximately 590.08 in^2.