To find the perimeter of the house, we need to calculate the distance between each pair of consecutive points and then add them up.
Using the distance formula:
AB = √((6-6)^2 + (-6-12)^2) = √(0^2 + (-18)^2) = √(0 + 324) = √324 = 18 yards
BC = √((6+4)^2 + (-6+6)^2) = √(10^2 + 0^2) = √(100 + 0) = √100 = 10 yards
CD = √((-4+4)^2 + (12+6)^2) = √(0^2 + 18^2) = √(0 + 324) = √324 = 18 yards
DA = √((-4-6)^2 + (12-12)^2) = √((-10)^2 + 0^2) = √(100 + 0) = √100 = 10 yards
Adding these up:
18 + 10 + 18 + 10 = 56
Therefore, the perimeter of the outside of the house is 56 yards.