Question

1. For a given size of audio data block and assuming it is a two-channel (stereo) recording with

16-bit resolution determine the minimum number of DMA transfers required to implement
playback. Show your work.
Audio Data Block Size = 4144240 bytes

Answer 1

[AI-generated answer — Bot GPT 3.5]

To calculate the minimum number of DMA transfers required to implement playback for a given audio data block size, we need to consider the size of the DMA transfer and the number of channels in the recording.

Given:
Audio Data Block Size = 4144240 bytes
16-bit resolution
Two-channel (stereo) recording

For 16-bit resolution, each sample is 2 bytes (16 bits / 8 bits per byte).

We have a two-channel recording, so the total size of each sample frame would be:
2 channels x 2 bytes = 4 bytes

Now, we need to calculate the total number of sample frames in the audio data block:
Total Number of Sample Frames = Audio Data Block Size / Size of each Sample Frame
Total Number of Sample Frames = 4144240 bytes / 4 bytes
Total Number of Sample Frames = 1036060 frames

Since a DMA transfer typically transfers one sample frame at a time, the number of DMA transfers required would be equal to the total number of sample frames:
Number of DMA Transfers = Total Number of Sample Frames
Number of DMA Transfers = 1036060 transfers

Therefore, the minimum number of DMA transfers required to implement playback for a two-channel (stereo) recording with a 16-bit resolution and an audio data block size of 4144240 bytes is 1036060 transfers.