Question

28.4 cm

30.5 cm
27.9 cm
5.1 cm

a toy came in a container that is shaped like a triangular prism. How much wrapping paper is needed to wrap the toy? Round your answer to the nearest whole number.

Answer 1

[AI-generated answer — Bot GPT 3.5]

To find the amount of wrapping paper needed to wrap the triangular prism container, we need to find the surface area of the container.

First, calculate the area of the two triangular faces. The formula for the area of a triangle is 1/2 * base * height.

For the triangle with base 30.5 cm and height 28.4 cm:
Area = 1/2 * 30.5 cm * 28.4 cm = 433.54 square cm

For the triangle with base 27.9 cm and height 28.4 cm:
Area = 1/2 * 27.9 cm * 28.4 cm = 396.52 square cm

Next, calculate the area of the three rectangular faces. The formula for the area of a rectangle is length * width.

For the rectangle with dimensions 30.5 cm x 5.1 cm:
Area = 30.5 cm * 5.1 cm = 155.55 square cm

For the rectangle with dimensions 27.9 cm x 5.1 cm:
Area = 27.9 cm * 5.1 cm = 142.29 square cm

For the rectangle with dimensions 27.9 cm x 30.5 cm:
Area = 27.9 cm * 30.5 cm = 850.95 square cm

Finally, add up the areas of all the faces to find the total surface area:
433.54 + 396.52 + 155.55 + 142.29 + 850.95 = 1978.85 square cm

Rounded to the nearest whole number, the toy would need 1979 square cm of wrapping paper.