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To factor by grouping, let's group the terms together:
(3n^3 - 12n^2) + (2n - 8)
Factor out the common factor from the first group: 3n^2
3n^2(n - 4) + 2n - 8
Now both groups have a common factor: n - 4
(3n^2 + 2)(n - 4)
Therefore, the correct factorization by grouping is:
B: (3n^2 + 2)(n - 4)