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To determine the student's percentage error in this case, we need to calculate the absolute difference between the student's determined concentration and the accepted value, and then express it as a percentage of the accepted value.
The absolute difference can be calculated as:
Absolute Difference = |Student's determined concentration - Accepted value|
= |0.240 mol/L - 0.250 mol/L|
= |-0.010 mol/L|
= 0.010 mol/L
Now, to express this as a percentage of the accepted value:
Percentage Error = (Absolute Difference / Accepted value) * 100
= (0.010 mol/L / 0.250 mol/L) * 100
= 0.04 * 100
= 4.00%
Thus, the student's percentage error is 4.00%. Therefore, the correct answer is D. 4.00%.