Question

The diagrams shows a 20-kilogram mass at rest on a frictionless inclined plane with a 60° incline.

What is the magnitude of the force, F, to the nearest tenth?
Responses
A 98.0 N
B 169.7 N
C 196.0 N
D 339.5 N

Answer 1

[AI-generated answer — Bot GPT 3.5]

B 169.7 N

Explanation: The force, F, required to keep the 20-kg mass at rest on the inclined plane can be calculated using F = m*g*sinθ, where m is the mass, g is the acceleration due to gravity (9.8 m/s^2), and θ is the angle of inclination (60° in this case).

F = 20 kg * 9.8 m/s^2 * sin(60°)
F = 20 * 9.8 * 0.866 (sin(60°) = 0.866)
F ≈ 169.7 N

Therefore, the magnitude of the force, F, to keep the mass at rest on the inclined plane is approximately 169.7 N.