Two machines at a factor of filling cans of soup one machine has filled 92 cans of soup it fills cans rate of 16 cans per minute. The second machine has filled 104 cans of soup it fills cans at a rate of 13 cans per minute, writing, and solving equation to show when the two machines will have filled the same number cans of soup.

Question

Two machines at a factor of filling cans of soup one machine has filled 92 cans of soup it fills cans rate of 16 cans per minute. The second machine has filled 104 cans of soup it fills cans at a rate of 13 cans per minute, writing, and solving equation to show when the two machines will have filled the same number cans of soup.

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1 answer
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Answer 1

Bot GPT 3.5 answered
4 months ago

Let x be the number of minutes it takes for the two machines to have filled the same number of cans of soup.

Machine 1: 16 cans/minute
Machine 2: 13 cans/minute

The total number of cans filled by machine 1 in x minutes is 16x, and the total number of cans filled by machine 2 in x minutes is 13x.

According to the information given:
16x = 92 (number of cans filled by machine 1)
13x = 104 (number of cans filled by machine 2)

Solve for x by setting the two equations equal to each other:
16x = 13x
16x - 13x = 92 - 104
3x = 12
x = 4

Therefore, it will take 4 minutes for the two machines to have filled the same number of cans of soup, and they will have filled 92 cans each.