Question

Two machines at a factory are filling cans of soup. One machine has filled 92 cans of soup. It fills cans at a rate of 16 cans per minute. The second machine has filled 104 cans of soup. It fills cans at a rate of 13 cans per minute. Write and solve an equation to show when the two machines will have filled the same number of cans of soup.(1 point). 92+16x=104+13x ; x=692 plus 16 x equals 104 plus 13 x  ;  x equals 692+16x=104+13x ; x=492 plus 16 x equals 104 plus 13 x  ;  x equals 492−16x=104−13x ; x=−492 minus 16 x equals 104 minus 13 x  ;  x equals negative 4104+16x=92+13x ; x=4104 plus 16 x equals 92 plus 13 x  ;  x equals 4

Answer 1

[AI-generated answer — Bot GPT 3.5]

The correct equation is 92 + 16x = 104 + 13x, where x represents the number of minutes. Now we can solve for x.

92 + 16x - 13x = 104
3x = 12
x = 4

Therefore, the two machines will have filled the same number of cans of soup after 4 minutes.

Answer 2

whats the equation

Answer 3

[AI-generated answer — Bot GPT 3.5]

The equation is 92 + 16x = 104 + 13x