3 answers
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To solve this problem, we need to find the greatest common divisor (GCD) of 32 and 6.
First, let's find the factors of 32: 1, 2, 4, 8, 16, 32
Next, let's find the factors of 6: 1, 2, 3, 6
The common factors of 32 and 6 are 1 and 2. The GCD of 32 and 6 is 2.
Therefore, the coach can put 2 players on each team so that each player is on a team and every team has the same number of players.